a.- $MA+KT=A(S+\color{red}{B}K)$ $→\displaystyle\frac{MA+KT}{A}=S+\color{red}{B}K$
$→\displaystyle\frac{MA+KT}{A}-S=\color{red}{B}K$
$→\displaystyle\frac{\frac{MA+KT}{A}-S}{K}=\color{red}{B}$ $→\color{red}{B}=\displaystyle\frac{\frac{MA+KT}{A}-S}{K}\color{red}\bullet$
b.- $\displaystyle B=\frac{L-2\color{red}{K}}{S-B}$
$→\displaystyle B(S-B)=L-2\color{red}K$
$→\displaystyle B(S-B)-L=-2\color{red}K$ multiplicando por $(-1)$
$→\displaystyle -B(S-B)+L=2\color{red}K$
$→\displaystyle -\frac{B(S-B)+L}{2}=\color{red}K$
$→\displaystyle\color{red}K= -\frac{B(S-B)+L}{2}\color{red}\bullet$
c.- $P(B+M)=RK+\displaystyle\frac{L.\color{red}{T}}{M}$
$→P(B+M)-RK=\displaystyle\frac{L.\color{red}{T}}{M}$
$→(P(B+M)-RK)M=L.\color{red}{T}$
$→\displaystyle\frac{(P(B+M)-RK)M}{L}=\color{red}{T}$
$→\displaystyle\color{red}{T}=\frac{(P(B+M)-RK)M}{L}\color{red}\bullet$
d.- $\displaystyle\frac{185}{5}$ $\mbox{mg } a\mbox{ Mg}$
$→37\mbox{ mg }\displaystyle\frac{Mg}{{10^{9}\mbox{ mg}}}$
$→\displaystyle\frac{37}{10^{9}}\mbox{ Mg}$ $→37\mbox{ mg}=3.7.10^{-8}\mbox{ Mg}\color{red}\bullet$
e.- $3\mbox{ h}\mbox{ y }35\mbox{ min}\mbox{ a}\mbox{ seg}$
$→3\mbox{ h }\displaystyle\frac{3600\mbox{ seg}}{\mbox{ h}}$ $→3\mbox{ h }=10800\mbox{ seg }\bullet$
$→35\mbox{ min }\displaystyle\frac{60\mbox{ seg}}{\mbox{ min}}$ $→35\mbox{ min }=2100\mbox{ seg }\bullet$
$→3\mbox{ h}\mbox{ y }35\mbox{ min}\mbox{ son }12900\mbox{ seg}\color{red}\bullet$
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